23.8k views
3 votes
Solve y2 = 15y − 56 using the quadratic formula.

2 Answers

6 votes

y^2 = 15y - 56\\\\y^2 - 15y + 56 = 0\\\\ (-b \pm √( b^2 -4( a)(c)) )/(2(a))\\\\ (15\pm √((-15)^2 -4(1)(56)) )/(2(1))\\\\ (15\pm √(1 ) )/(2)\\\\ (15\pm 1 )/(2)\\\\(16)/(2), (14)/(2)\\\\8, 7

The solution is 7 and 8.
User Romo
by
8.5k points
4 votes
y^2= 15y -56
⇒ y^2 -15y+ 56= 0
⇒ y= \frac{-(-15)+ \sqrt{(-15)^2-4(1)(56)} }{2*1}
or y= \frac{-(-15)- \sqrt{(-15)^2-4(1)(56)} }{2*1}
⇒ y= 8 or y= 7

The final answer is y= 8 or y= 7~
User Mehmet Guloglu
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories