Recall the equation,
x = a^y
This is an exponential equation. To write it as a logarithmic function, it becomes
y = loga x
where
a is the base of the logarithm
The given exponential equation is
1/64 = (1/4)^3
By comparing both equations, we have
a = 1/4, y = 3, x = 1/64
Thus, in logarithmic form, the equation is
3 = log(1/4) 1/64
where
1/4 is the base of the logarithm