Question

23g of sodium reacted with 35.5g of chlorine. Calculate the mass of the sodium chloride compound formed.

Answer 1

58.5 is the final mass of the compound as long as any gases the reaction causes to be

Answer 2

Answer: The mass of sodium chloride formed will be 58.5 g

Step-by-step explanation:

To calculate the number of moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}` .....(1)

• For Sodium:

Given mass of sodium = 23 g

Molar mass of sodium = 23 g/mol

Putting values in equation 1, we get:

`\text{Moles of sodium}=(23g)/(23g/mol)=1mol`

• For chlorine gas:

Given mass of chlorine gas = 35.5 g

Molar mass of chlorine gas = 71 g/mol

Putting values in equation 1, we get:

`\text{Moles of chlorine gas}=(35.5g)/(71g/mol)=0.5mol`

The chemical reaction for the formation of sodium chloride follows the equation:

`2Na+Cl_2\rightarrow 2NaCl`

By stoichiometry of the reaction:

2 moles of sodium reacts with 1 mole of chlorine gas.

So, 1 mole of sodium will react with =
`(1)/(2)* 1=0.5mol` of chlorine gas.

Thus, the formation of sodium chloride can be calculated by using any of the reactant.

By stoichiometry of the reaction:

2 moles of sodium produces 2 moles of sodium chloride.

So, 1 mole of sodium will react with =
`(2)/(2)* 1=1mol` of sodium chloride.

Now, calculating the mass of sodium chloride by using equation 1, we get:

Moles of sodium chloride = 1 mole

Molar mass of sodium chloride = 58.5 g/mol

Putting values in equation 1, we get:

`1mol=\frac{\text{Mass of NaCl}}{58.5g/mol}\\\\\text{Mass of NaCl}=58.5g`

Hence, the mass of sodium chloride formed will be 58.5 g