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Write an equation for the line that passes through (5, 1) and (6, 3). Please show me how to do it!

User Rroche
by
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1 Answer

1 vote
this is the equation that in the end it needs to be y=mx+b mx~slope b~ intersecting on y

1. label then x1,y1 , x2,y2
(5, 1) (6, 3)
x1 y1 x2 y2

2. plug them in this formula
m= y2-y1
--------
X2,x1
m= 3-1
-------
6-5
m= 2
_____ slope is 2
1

y= 2x+ b. ( to find b take one of the cordiants )
-using (5,1)
- 1= 2(5)+b
- 1=10+b (subtract 10 on both sides)
- -9 =b. ( now you have b )

y=2x -9


easier way maybe would be to put it in a chart to find slope x|y ------ it goes 6|3 goes down 2 down one 5|1 rise. =y 2 ---------- - = 2. slope is 2. follow the run= x. 1. steps before to find b
User Muetzerich
by
7.3k points

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