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Rewrite with positive exponents, and simplify, if possible.


((8xz)/(9y))^(-1/2)

User Vaughan
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1 Answer

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\left((8xy)/(9y)\right)^{-(1)/(2)}=\left((9y)/(8xz)\right)^(1)/(2)=(√(9y))/(√(8xz))=(3√(y))/(√(4\cdot2xz))=(3√(y))/(2√(2xz))\cdot(√(2xz))/(√(2xz))=(3√(2xyz))/(2\cdot2xz)=(3√(2xyz))/(4xz)
User Shakti Raj Singh
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