Question

A hot water heater measures 20" in diameter. What is the area of a metal base for the water heater, assuming a four-inch overhang for the base beyond the edge of the heater? (Round to the nearest tenth.)

Answer 1

A four-inch part is connected around the hot water heater as to expand. So d = 20 + 4 + 4 = 28 inches.

The area of a circle is A = π(d/2)^2
A = π(28/2)^2 = 3615.7521... inches = 3620 inches (rounded to the nearest tenth)

Answer 2

`307.72 in^2\\`

Explanation:

The diameter of hot water heater
`= 20`

There is overhang of
`4`

Thus the new extended radius of the base of hot water heater is

`= (20`

The heater must be of circular shape, thus the area of the water heater

`=\pi r^(2) \\= \pi ((d)/(2))^2\\= (3.14)(0.5)(14`