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How many moles of sulfate ions (SO42−) are present in 1.5 mol of Al2(SO4)3?
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How many moles of sulfate ions (SO42−) are present in 1.5 mol of Al2(SO4)3?

User Bravenewweb
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2 Answers

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1.5 mol* 3= 4.5 mol.

There is 4.5 mol of SO42- in 1.5 mol of Al2(SO4)3~
User Leikingo
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6 votes
Multiply moles by coefficient. 4.5mol
User Chukky Nze
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