Final answer:
To solve for a division problem with a quotient of 3 and a remainder of 28, you can use a divisor less than the remainder and apply the formula dividend = divisor × quotient + remainder. Using a divisor of 10, the dividend would be 58. Thus, 58 divided by 10 equals a quotient of 3 and a remainder of 28.
Step-by-step explanation:
To find a division problem that has a quotient of 3 and a remainder of 28, you need to use long division or understand the relationship between division, quotients, and remainders. The formula for this is dividend = divisor × quotient + remainder. If you're given a quotient of 3 and a remainder of 28, you can select any divisor that is smaller than the remainder to construct such a problem. Let's choose a divisor of 10 for simplicity.
Following the formula:
dividend = (10 × 3) + 28
dividend = 30 + 28
dividend = 58.
Thus, 58 divided by 10 equals a quotient of 3 with a remainder of 28.