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Please help me answer this ASAP! The two-way table shows the number of ninth and tenth graders who prefer going to sporting events or going to the movies.

Among tenth graders, what is the relative frequency of preferring sporting events? Express your answer as a decimal, and round to the nearest hundredth if necessary

Please help me answer this ASAP! The two-way table shows the number of ninth and tenth-example-1
User Dbro
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2 Answers

2 votes

Answer:

0.43

Explanation:

I took the k12 quiz

User Daniel Robertson
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6 votes

Answer

0.43

Explanation

Remember that
RelativeFrecuency=(Frecuency)/(SumOfAllFrecuencies)

Since the problem is telling us "Among tenth graders", we must focus on the 10th graders row only. From the row, we can infer that the frequency is the number of 10th graders who prefer going to sporting events, so
Frecuency=6. Now, the sum of all frequencies will be the sum of all the 10th graders, so
SumOfAllFrecuencies=6+8=14. Let's replace the values:


RelativeFrecuency=(Frecuency)/(SumOfAllFrecuencies)


RelativeFrecuency=(6)/(14)


RelativeFrecuency=0.4285

And rounded to the nearest hundredth:


RelativeFrecuency=0.43

User Thennan
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