If f(x)=8sin^6x - cos^2x. Find f'(\pi /4.

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asked Dec 4, 2017 181k views

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Tobias Leupold · Answer 1 · 2017-12-08T22:14:00+0000

f'(x) = 48(sin(x))^5*cos(x)- 2cos(x)(-sin(x))
= 48(sin(x))^5*cos(x)+ 2cos(x)sin(x)

f'(π/4)= 48(sin(π/4))^5*cos(π/4)+ 2cos(π/4)sin(π/4)=7.

The final answer is 7.

Hope this helps~

If f(x)=8sin^6x - cos^2x. Find f'(\pi /4.

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