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If x=at^3 and y=bt^2 then find dy/dx

If x=at^3 and y=bt^2 then find dy/dx
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If x=at^3 and y=bt^2 then find dy/dx

User Mikael S
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dy/dx = (dy/dt) / (dx/dt)

dy/dt = 2bt

dx/dt = 3at^2

therefore dy/dx = 2bt/3at^2
dy/dx = 2b/3at
User Emilio M Bumachar
by
8.7k points
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