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 bisects EOG. EOF = y + 30 and FOG = 3y – 50. Solve for y.

  20
70
40
50




2 Answers

0 votes
since given it bisects EOF must be equal to FOG

y+30 = 3y-50

2y = 80

y = 40
User CodingCat
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7.7k points
3 votes

Answer: the correct option is (C) 40.

Step-by-step explanation: As shown in the attached figure below, the line OF bisects the angle EOG, where


m\angle EOF=y+30,\\\\m\angle FOG=3y-50.

We are to find the value of y.

Since OF is the bisector of the angle EOG, so it divides the angle EOG into two congruent angles.

Therefore, we get


m\angle EOF=m\angle FOG\\\\\Rightarrow y+30=3y-50\\\\\Rightarrow 3y-y=30+50\\\\\Rightarrow 2y=80\\\\\Rightarrow y=(80)/(2)\\\\\Rightarrow y=40.

Thus, the value of y is 40.

Option (C) is CORRECT.

bisects EOG. EOF = y + 30 and FOG = 3y – 50. Solve for y. 20 70 40 50-example-1
User Jason Tyler
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8.3k points