Question

using the equation Mg3N2 + 3K2O = 3MgO + 2K3NWhen you start with 12.5 moles of potassium oxide, how many grams of magnesium oxide will you produce?

Answer 1

We have the following chemical equarion:

`Mg_3N_2+3K_2O\rightarrow3MgO+2K_3N`

The first thing we do is check if the equation is balanced. As we can see we have the same number of each element on each side of the equation, so it is balanced.

Now, we know that for every 3 moles of potassium oxide that react 3 moles of magnesium oxide are produced. Therefore if 12.5 moles of potassium oxide react, 12.5 moles of magnesium oxide will be produced.

To answer the question we have to calculate the mass. This we do by using the molecule's molar mass (M).

Magnesium oxide's molar mas is:

`M=M_(Mg)+M_O=24.3(g)/(mol)+16(g)/(mol)=40.3(g)/(mol)`

Now we calculate the mass (m):

`m=n.M=12.5mol.40.3(g)/(mol)=503.75g`

So the answer is 503.75g