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a metal alloy weighing 6 mg and containing 32% gold is melted and mixed with 12 mg of a different alloy which contains 2% gold. what % of the resulting alloy is gold? explain all of your work.

User JstnPwll
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1 Answer

12 votes
12 votes

12% of the resulting alloy is gold

Here, we want to calculate the percentage of the resulting alloy that is gold

We proceed as follows;

(32% of 6mg) + (2% of 12mg)

That would be;

1.92 + 0.24 = 2.16

What means that of the total (6mg + 12mg) , 2.16 mg is gold

Thus the gold percentage will be;


(2.16)/(18)\text{ }*\text{ 100 = 12 percent}

User Anqi Lu
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