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If there are 12 teams in a basketball tournament and each team must play every other team in the eliminations, how many elimination games will be?

User Freddie
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2 Answers

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Answer:Jaguar

Explanation:

User Kabucey
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In each game, the first team can be any one of the 12 ,
and the second team can be any one of the remaining 11 .

Total number of ways to match them up = (12 x 11) = 132 .

BUT ... Every game can be described as two different match-ups ...
either as ' A ' playing ' B' , or as ' B ' playing ' A '.

Although there are 132 ways to make a match-up, every possible
pair of teams shows up twice in that list.

So in order for every team to play every other team, there are
only (132 / 2) = 66 different games required.

User Gavo
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