Question

A particle moves along a line so that its position at any time t > 0 is given by the function s(t) = - t3 + 7t2 - 14t +8 where s is measured in meters and t is measured in seconds. Find the displacement during the first 5 seconds.

Answer 1

s(5) = -12

Explanation:

s(t) = - t³ + 7t² - 14t +8

Find the displacement during the first 5 seconds.

When t = 5

s(t) = - t³ + 7t² - 14t +8

s(5) = -5³ + 7(5)² - 14(5) + 8

= -125 + 7(25) - 70 + 8

= -125 + 175 - 70 + 8

= -12

s(5) = -12