Question

A 0.0600-kilogram ball traveling at 60.0 meters

per second hits a concrete wall. What speed
must a 0.0100-kilogram bullet have in order to
hit the wall with the same magnitude of
momentum as the ball?
(1) 3.60 m/s (3) 360. m/s
(2) 6.00 m/s (4) 600. m/s

Answer 1

The momentum of ball is given by:


`\Delta Q=mv \\ \Delta Q=6*10^(-2)*60 \\ \Delta Q=3.6kg*m/s`

Since both have the same momentum, we have:


`\Delta Q=MV \\ 3.6=10^(-2)V \\ \boxed {V=360m/s}`

Number 3

If you notice any mistake in my english, please let me know, because i am not native.