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Find the roots of the equation 3x^2 + 45 = 0.

Find the roots of the equation 3x^2 + 45 = 0.-example-1
User Amol Bhor
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1 Answer

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+i√(15)\text{ ,-i}√(15)

Step-by-step explanation

A root is a value for which a given function equals zero, so let's solve the equation

Step 1


3x^2+45=0

a) apply the subtraction property of equality and subtract 45 in both sides


\begin{gathered} 3x^2+45=0 \\ 3x^2+45-45=0-45 \\ 3x^2=-45 \end{gathered}

b)now, use the division property of equality to isolate square x,


\begin{gathered} 3x^2=-45 \\ divide\text{ both sides by 3} \\ (3x^2)/(3)=(-45)/(3) \\ x^2=-15 \end{gathered}

c) finally , take the square root in both sides


\begin{gathered} x^(2)=-15 \\ √(x^2)=√(-15) \\ x=\pm√(15)i \\ x=\pm i√(15) \end{gathered}

so, the answer is


+i√(15)\text{ ,-i}√(15)

I hope this helps you

User Krizz
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