Question

A net charge of 5.0 coulombs passes a point on a

conductor in 0.050 second. The average current is
(1) 8.0 × 10^−8 A (3) 2.5 × 10^−1 A
(2) 1.0 × 10^−2 A (4) 1.0 × 10^2 A

Answer 1

Answer: 1.0 x 10^2

Step-by-step explanation:

Answer 2

Answer : The average value of current is
`1.0* 10^2\ A`.

Explanation :

It is given that,

Net charge, q = 5 C

Time, t = 0.05 s

The electric current is defined as the rate of change of electric charge.

`I=(q)/(t)`

`I=(5\ C)/(0.05\ s)`

`I = 100\ A`

or

`I=1.0* 10^2\ A`

The average current is
`1.0* 10^2\ A`.

Hence, this is the required solution.