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The value in dollars, v(x), of a certain car after x years is represented by the equation v(x) = 25,000(0.86)^x. To the nearest dollar, how much more is the car worth after 2 years than after 3 years?
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The value in dollars, v(x), of a certain car after x years is represented

by the equation v(x) = 25,000(0.86)^x. To the nearest dollar,
how much more is the car worth after 2 years than after 3 years?
(1) 2589 (3) 15,901
(2) 6510 (4) 18,490

User Gregory Schultz
by
8.4k points

2 Answers

1 vote

Answer:

2589

Explanation:

User Ajithkumar S
by
8.3k points
5 votes
After 2 years: x=2
v(2)= 25,000(0.86)^2= 18,490

After 3 years: x=3
v(3)= 25,000(0.86)^3= 15,901.4

18,490 - 15,901.4= 2,588.6

Rounded to the nearest dollar, the answer is (1) 2589 dollars.

Hope this helps~
User Ayhan APAYDIN
by
8.8k points
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