Question

How much total energy is dissipated in 10. seconds

in a 4.0-ohm resistor with a current of
0.50 ampere?
(1) 2.5 J (3) 10. J
(2) 5.0 J (4) 20. J

Answer 1

3) 10 J

Step-by-step explanation:

Electrical energy dissipated is given as

`U = i^2 R T`

here we know that

i = electrical current = 0.50 A

R = 4 ohm

T = 10 s

so we have electrical energy given as

`U = (0.50)^2(4)(10)`

`U = 10 J`

Answer 2

Answer : Total energy dissipated is 10 J

Explanation :

It is given that,

Time. t = 10 s

Resistance of the resistors, R = 4-ohm

Current, I = 0.5 A

Power used is given by :

`P=(E)/(t)`

Where

E is the energy dissipated.

So, E = P t.............(1)

Since,
`P=I^2R`

So equation (1) becomes :

`E=I^2Rt`

`E=(0.5\ A)^2* 4\Omega * 10\ s`

`E=10\ J`

So, the correct option is (3)

Hence, this is the required solution.