190k views
5 votes
Find the domain and range for the absolute value function f(x)=| x+2 |-3

User Qijun Liu
by
8.4k points

1 Answer

4 votes
f(x) = |x + 2| - 3
0 = |x + 2| - 3
0 = x + 2 - 3
0 = x - 1
+ 1 + 1
1 = x

Domain: x > 1 and x < 1
Solution Set of the Domain: x and x or (1, 1)

f(x) = |x + 2| - 3
f(x) = |0 + 2| - 3
f(x) = |2| - 3
f(x) = 2 - 3
f(x) = -1

Range: x ≤ 3
Solution Set of the Range: x ≤ 3 or (-∞, 3]
User Seymour
by
9.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories