Question

A taxicab starts at (1, -2) on the grid. It goes 3 blocks east and 1 block south to pick up a passenger. Then it goes 6 blocks west and 5 blocks north and drops off the passenger. What are the coordinates of the point where the passenger was dropped off?

Answer 1

The coordinates of the point where the passenger was dropped of is the point (-2, 2).

(1, -2) + (3, -1) = ((1 + 3), (-2 - 1)) = (4, -3)
(4, -3) + (-6, 5) = ((4 - 6), (-3 + 5)) = (-2, 2)

Answer 2

Answer: The co-ordinates of the point where the passenger was dropped are (-2, 2).

Step-by-step explanation: Given that a taxicab starts at (1, -2) on the grid. It goes 3 blocks east and 1 block south to pick up a passenger.

After that, it goes 6 blocks west and 5 blocks north and drops off the passenger.

We are to find the coordinates of the point where the passenger was dropped off.

3 blocks East: When the taxicab goes 3 blocks east, then the the co-ordinates of the point becomes

(1, -2) ⇒ (1+3, -2) = (4, -2).

1 block South: When the taxicab goes 1 block South, then the the co-ordinates of the point becomes

(4, -2) ⇒ (4, -2-1) = (4, -3).

6 blocks West: When the taxicab goes 6 blocks West, then the the co-ordinates of the point becomes

(4, -3) ⇒ (4-6, -3) = (-2, -3).

5 blocks North: When the taxicab goes 5 blocks South, then the the co-ordinates of the point becomes

(-2, -3) ⇒ (-2, -3+5) = (-2, 2).

Thus, the co-ordinates of the point where the passenger was dropped are (-2, 2).