Question

A 6-ohm resistor and a 4-ohm resistor are

connected in series with a 6-volt battery in an
operating electric circuit. A voltmeter is
connected to measure the potential difference
across the 6-ohm resistor.
In the space in your answer booklet, draw a
diagram of this circuit including the battery,
resistors, and voltmeter using symbols from the
Reference Tables for Physical Setting/Physics.
Label each resistor with its value. [Assume the
availability of any number of wires of negligible
resistance.]

Answer 1

The current flowing in the circuit is given by the Ohm's First Law.


`i_(eq)= (V)/(R_(eq)) \\ i_(eq)= (6)/(4+6) \\ i_(eq)= 0.6A`

The current flowing in the 6-ohm resistor is the total current of circuit, therefore the voltage drop across this resistor is given by:


`V_(6)=R_(6)*I_(eq) \\ V_(6)=6*0.6 \\ \boxed {V_(6)=3.6V}`

Obs: the drawing is attached

If you notice any mistake in my english, please let me know, because i am not native.