Question

Skye's two new aquariums each hold exactly 200 gallons of water. One aquarium will hold small fish and the other will hold large fish. Now hew needs new fish for his aquariums. She will buy 5 small fish for every 10 gallons of water in the aquarium. She will buy 8 large fish for every 40 gallons of water in the aquarium. What is the total number of fish Skye will have?

Answer 1

In terms of the first aquarium, the number of small fish Skye will have is:
200 gallons of water* (5 small fish/ 10 gallons of water)= 100 small fish.

In terms of the second aquarium, the number of large fish Skye will have is:
200 gallons of water* (8 large fish/ 40 gallons of water)= 40 large fish.

The total number of fish Skye will have is:
100 fish+ 40 fish= 140 fish.

Final answer: 140 fish.

Hope this would help~

Answer 2

Answer=140 fish

200 gallons of water in the first aquarium.

200 gallons of water in the second aquarium.

The first will be for the small fishes.

5 small fish x fish
_____________=__________
10 gallons 200 gallons

cross multiply
10x=1000
divide both sides by 10
x=100 small fish

The first aquarium has 100 small fish.

The second aquarium holds large fish.

8 large fish x fish
____________=___________
40 gallons 200 gallons

cross multiply
40x=1600
divide both sides by 40
x=40 large fish

The second aquarium has 40 large fish.

100small fish+40 large fish=140 total fish