Question

A student intended to make a salt solution with a concentration of 10.0grams of solute per liter of solution. When the student’s solution wasanalyzed, it was found to contain 8.90 grams of solute per liter of solution.What was the percent error in the concentration of the solution?(1) 1.10% (3) 11.0%(2) 8.90% (4) 18.9%

Answer 1

Take the absolute value of 10.0 - 8.90/10.0 to get 0.11 then multiply that by 100 percent to get 11 percent

Answer 2

The % error is = 11.0 %

calculation

percentage error = (Exact value -Approximate value) / exact amount x100

Approximate value = 8.9 g
Exact value = 10.0 g
Percentage error is therefore = {(10.0 - 8.9) /10.0} x100

(1.1 g/ 10.0) x100 = 0.11 x100 = 11.0%