Question

When a spring is compressed 2.50 × 10^–2 meter

from its equilibrium position, the total potential
energy stored in the spring is 1.25 × 10^–2 joule.
Calculate the spring constant of the spring.
[Show all work, including the equation and
substitution with units.]

Answer 1

The working of a spring is given by:


`T_(el)= (k\Delta x^2)/(2)`

Entering the unknowns, we have:


`T_(el)=(k\Delta x^2)/(2) \\ 1.25*10^(-2)*2*J=k(2.5*10^(-2)m)^2 \\ k= (2.5*10^(-2)*J)/((2.5*10^(-2)m)^2) \\ k=40* (J)/(m^2) \\ k=40 (N*m)/(m^2) \\ \boxed {k=40* (N)/(m) }`

If you notice any mistake in my english, please let me know, because i am not native.