Question

Which is the standard form of the equation of the parabola that has a vertex of (–4, –6) and a directrix of y = 3?

Answer 1

a

Explanation:

i got it right on edge

Answer 2

We use the form
`(y-k)^2 = 4p(x-h)` when
`(h,k)` is the vertex, p is the distance between the focus and the vertex. We know this because this is a parabola that opens to the left, along the x axis. The directrix is the same distance away from the vertex (in terms of its perpendicular line from it to the vertex) as the focus, so p = 9, since |-6 - 3| = 9 (perpendicular distance from directrix to vertex). We know the vertex is (-4,-6), so we apply all of these values to get the standard form:


`(x+4) = 36(y+6)^2`