Final answer:
When 1-bromobutane reacts with magnesium, acetone, and aqueous acid sequentially, the final product is 2-methyl-2-butanol. This process involves the formation of a Grignard reagent and subsequent reaction with acetone to produce the tertiary alcohol.
Step-by-step explanation:
When 1-bromobutane is exposed to magnesium, followed by acetone and then aqueous acid, the resulting product is a Grignard reagent followed by a tertiary alcohol after the entire reaction sequence. This process is a combination of a Grignard reaction and a subsequent hydration step.
The reaction sequence involves the formation of a Grignard reagent by the reaction of 1-bromobutane with magnesium in an ether solvent such as diethyl ether or THF (tetrahydrofuran). This results in butylmagnesium bromide. The Grignard reagent then reacts with acetone, a ketone, to form a tertiary alcohol after an aqueous acid is added to protonate the alkoxide intermediate. The final product of this sequence is 2-methyl-2-butanol.
This type of reaction is useful for forming carbon-carbon bonds and is widely used in organic synthesis. The Grignard reagent acts as a nucleophile, attacking the electrophilic carbon in the carbonyl group of acetone, which after subsequent steps leads to the formation of the new alcohol.