Question

A sample of mercury is heated from 25.5 °C to 52.5 °C. In the process, 3050J of heat

are absorbed. What mass of mercury was in the sample? The specific heat of mercury is 140 J/g °C.

Answer 1

3050÷140 =21.79g Therefore the was a mass of 21.79 grams in the sample

Answer 2

0.807g

Step-by-step explanation:

They tell us that we heat the sample and during this process its state of aggregation does not change so we are facing a sensible heat

sensible heat formula

`Q=m.C_e.\Delta t\\Q=m.C_e.(T_f-T_o)`

Data

`Q=3050J\\C_e= 140J/g\ºC\\T_o= 25.5\ºC\\T_f=52.5\ºC`

We clear the mass of the sensible heat formula

`Q=m.C_e.\Delta t\\(Q)/(C_e.\Delta t)=m\\`

`(3050J)/(140J/g\ºC.(52.5-25.5)\ºC)=m\\0.807 g= m`

The mass of the mercury sample is 0.807g