Question

A number is thrice the second number. The second number is also twice the third number. If the average of the three numbers is 18, find the numbers.

Answer 1

x - 1st number
y - 2nd number
z - 3rd number


`x=3y\\ y=2z\\ (x+y+z)/(3)=18\\\\ x=3y\\ z=(y)/(2)\\ x+y+z=54\\\\ 3y+y+(y)/(2)=54\\ 6y+2y+y=108\\ 9y=108\\ y=12\\\\ z=(12)/(2)\\ z=6\\\\ x=3\cdot12\\ x=36\\\\ \boxed{36,12,6}`