given the equation of a circle x^2+y^2-10x+4y+13=0. find its center and radius. i am having trouble please help

asked Jan 21, 2015 224k views

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$x^2+y^2-10x+4y+13=0\\ x^2-10x+25+y^2+4y+4-16=0\\ (x-5)^2+(y+2)^2=16\\\\ \hbox{center}=(5,-2)\\ r=4$

Gordon Yorke answered Jan 26, 2015

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