Question

2. How many moles of HCI are needed to react with 0.47 g of NaHC03 ?

Answer 1

HCl reacts with NaHCO₃ this way:

`HCl_{}+NaHCO_3\rightarrow NaCl+H_2O+CO_2`

The equation is already balanced, it means that 1 mole of HCl reacts with 1 mole of NaHCO₃.

Convert the mass of NaHCO₃ to moles using the molecular mass of NaHCO₃ which is 84g/mol.

`0.47g\cdot(1mol)/(84g)=0.0056mol`

Now, use the ration stated before to find how many moles of HCl react with this amount of NaHCO₃:

`0.0056mol\cdot(1mol)/(1mol)=0.0056mol`

It means that 0.0056 moles of HCl are needed to react with 0.47g of NaHCO₃.