Question

Using the quadratic equation x2-3x+2=0 perform the following tasks:

solve by factoring.
solve by completing the square.

Answer 1

`x^2-3x+2=0\\ x^2-x-2x+2=0\\ x(x-1)-2(x-1)=0\\ (x-2)(x-1)=0\\ x=2 \vee x=1\\\\\ x^2-3x+2=0\\ x^2-3x+(9)/(4)-(1)/(4)=0\\ (x-(3)/(2))^2=(1)/(4)\\ x-(3)/(2)=\sqrt{(1)/(4)} \vee x-(3)/(2)=-\sqrt{(1)/(4)}\\ x-(3)/(2)=(1)/(2) \vee x-(3)/(2)=-(1)/(2)\\ x=(4)/(2) \vee x=(2)/(2)\\ x=2 \vee x=1`