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Which value of k satisfies the equation 8^3k + 4 = 4^2k-1

User Zkurtz
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2 Answers

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8^(3k + 4) = 4^(2k -1) \\ \\ 2^(3(3k+4)) = 2^(2(2k-1)) \\ \\ 2^(9k + 12) = 2^(4k-2) \\ \\ 9k+12 = 4k-2 \\ \\ 5k = -14 \\ \\ \boxed{k = - (14)/(5) }
User CamelCaseD
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If you would like to solve the equation 8^3 * k + 4 = 4^2 * k - 1, you can calculate this using the following steps:

8^3 * k + 4 = 4^2 * k - 1
8^3 * k - 4^2 * k = - 1 - 4
512 * k - 16 * k = - 5
496 * k = - 5 /496
k = - 5/496

The correct result would be - 5/496.
User Epaga
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