Question

I really need help on this question can you help

Answer 1

To solve the equation:

`-2x^2-16x-44=0`

we use the general formula:

`x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}`

In the equation given we have that a=-2, b=-16 and c=-44. Plugging the values in the general equation we have:

`\begin{gathered} x=\frac{-(-16)\pm\sqrt[]{(-16)^2-4(-2)(-44)}}{2(-2)} \\ =\frac{16\pm\sqrt[]{256-352}}{-4} \\ =\frac{-16\pm\sqrt[]{-96}}{4} \\ =\frac{-16\pm\sqrt[]{6\cdot16}i}{4} \\ =\frac{-16\pm4\sqrt[]{6}i}{4} \\ =-(16)/(4)\pm(4)/(4)\sqrt[]{6}i \\ =-4\pm\sqrt[]{6}i \end{gathered}`

Therefore the answer is the third option