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17 votes
17 votes
How much charge is transferred by a 0.80 A current in 19 minutes?

User Djamel
by
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1 Answer

19 votes
19 votes

Given that the current is I = 0.80 A

and the time taken is


\begin{gathered} t\text{ = 19 minutes} \\ =19*60\text{ seconds} \\ =1140\text{ s} \end{gathered}

We have to find the charge, q.

The formula to calculate the charge is


q=I* t

Substituting the values, the charge will be


\begin{gathered} q\text{ = }0.80*1140 \\ =912\text{ C} \end{gathered}

Thus, the charge is 912 C.

User Theplau
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3.0k points