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How do you solve the function y = 2.5^x for y=20
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How do you solve the function y = 2.5^x  for y=20 

User Payne
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y=2.5^x;\ y=20\\\\2.5^x=20\\\\log_(2.5)2.5^x=log_(2.5)20\\\\x=log_(2.5)20\\\\x=log_(2.5)(2.5\cdot8)\\\\x=log_(2.5)2.5}+log_(2.5)8\\\\x=1+log_(2.5)8
User Applejuiceteaching
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