Question

Simplify.

A.
–28xy

B.
–28

C.
28xy

D.
27

Answer 1

`\left(-(1)/(2)\right)(4x)(-2)(7y)(-1)\\\\=\left(-(1)/(2)\right)(-2)(4)(7)(-1)(x)(y)\\\\=(1)(4)(7)(-1)(xy)\\\\=(28)(-1)(xy)\\\\=(-28)(xy)\\\\=\boxed{-28xy}\to\boxed{\boxed{A}}`

Answer 2

Your attachment says: (-1/2) · (4x) · (-2) · (7y) · (-1)

Let's put together the
1st, 3rd, and 5th factors: (-1/2) · (-2) · (-1) = -1

So now we have (-1) · (4x) · (7y)

Well (4x) · (7y) = (4 · 7) · (x · y) = 28 · x · y

So all together we have (-1) · (28 · x · y) = -28xy