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There are 8 students in a classroom, including the triplets Molly, Polly, and Dolly. If 3 of the 8 are randomly selected to give speeches, what is the probability that Molly will be first, Polly will be
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Sep 2, 2016
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There are 8 students in a classroom, including the triplets Molly, Polly, and Dolly. If 3 of the 8 are randomly selected to give speeches, what is the probability that Molly will be first, Polly will be second, and Dolly will be third?
Mathematics
high-school
MattiasF
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1/336 ~~~~~~~~~~~~~~~~~~~~~~ APEX
Guillaume Badi
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Sep 3, 2016
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Guillaume Badi
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The way you figure this out is that the first person picked has a 1/8 chance, the second would be 1/7 (one person already went) and the third person would have a 1/6 chance (two people already went). To find the probability of this happening would be all the odds multiplied together, so (1/8)*(1/7)*(1/6) which equals 1/336
Tomek Cejner
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Sep 8, 2016
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Tomek Cejner
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