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Find the equation of the line that goes through (-6,8) and is perpendicular to y=-3/2x-4

User Javier Vieira
by
2.9k points

1 Answer

14 votes
14 votes

find the equation of the line that goes through (-6,8) and is perpendicular to y=-3/2x-4​

step 1

Find teh slope of the given line

y=(3/2)x-4

the slope is m=3/2

Remember that, if two lines are perpendicular, then their slopes are opposite reciprocal

so

the slope of the perpendicular line is

m=-2/3

step 2

Find the equation of the line in slope intercept form

y=mx+b

we have

m=-2/3

point (-6,8)

substitute the given values

8=-(2/3)*(-6)+b

solve for b

8=4+b

b=4

therefore

the equation of the perpendicular line is

y=-(2/3)x+4

User Andrey Ermakov
by
3.1k points
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