Question

Arthur puts new batteries in his flashlight before leaving the house. Until the batteries die, it draws 0.25 A of current, allowing a total of 6,812 C of charge to. flow in the circuit. How long will Arthur be able to use the flashlight before the batteries'energy is depleted?

Answer 1

Given,

The current, I=0.25 A

The total charge flowing in the circuit is q=6812 C.

The electric current can be defined as the time rate of flow of the charges.

Thus, the electric current is given by,

`I=(q)/(t)`

Where t is the time duration.

`\begin{gathered} 0.25=(6812)/(t) \\ t=(6812)/(0.25) \\ =27248\text{ s} \end{gathered}`

Thus the batteries will fry out after 27248 s