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What volume would 3.01•1023 molecules of oxygen gas occupy at STP?

User SergeyK
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2 Answers

4 votes

hi the answer is c) 11.2 L do NOT put mL i got it wrong

User Zhyfer
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Answer: C. 11.2 L

Step-by-step explanation:

According to Avogadro's number there are ~6.022 * 10^23 atoms/molecules per mol.

6.022/2 ≅ 3.01, so that means there is half of a mole of oxygen gas. To convert between moles and liters at standard temperature and pressure (STP), multiply the number of mol by 22.4 (the number of liters a single mole of any gas would occupy at STP).

0.5 x 22.4 = 11.2

The units of our final answer would be in liters, so...

3.01 * 10^23 molecules of oxygen gas occupy 11.2 L at STP.

User ZachOfAllTrades
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