Question

Calculate the height from which a body is released from rest if its velocity just before hitting the ground is 30ms

Answer 1

S= ?
U= 0
`ms^(-1)`
V= 30
`ms^(-1)`
A= 9.8
`ms^(-2)`
T=


`V^2 = U^2 + 2AS`

`900 = 19.6S`

`(900)/(19.6) = S`
S = 45.92
`m`