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Find the missing endpoint given one endpoint and midpoint

2)
endpoint- ( -4,1) midpoint-(-1,3)

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endpoint: \ ( x_(2),y_(2))= (-4,1) , \\ midpoint : \(x,y)=(-1,3) \\\\Mindpoint \ Formula : \\ (x,y)=\left ( (x_(1)+x_(2) )/(2), \frac{y_ {1}+y_(2) }{2} \right )\\\\(-1,3)=\left ( (x_(1)-4 )/(2), \frac{y_ {1}+1 }{2} \right )


\begin{cases} (x_(1)-4 )/(2)= -1 \ \ /\cdot 2 \\ \frac{y_ {1}+1 }{2} =3 \ \ / \cdot 2 \end{cases}\\\\\begin{cases} x_(1)-4 =-2 \\ y_ {1}+1 =6\end{cases}\\ \\\begin{cases} x_(1) =-2+4 \\ y_ {1} =6-1 \end{cases}\\ \\\begin{cases} x_(1) =2\\ y_ {1} =5 \end{cases} \\ \\Answer : \ second \ endpoint : \ (x_(1),y_(1))=(2,5)

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