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Find the sum of the multiples of 3 from 3 to 99 inclusive

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Multiples of 3 from 3 to 99 inclusive is a Aritmetic Progression where:

a1 = 3
an = 99
r = 3

Using the formula of general terms:


a_n=a_1+(n-1).r\\ \\ 99=3+3(n-1)\\ \\ 99-3=3n-3\\ \\ 3n=99\\ \\ n=33

Calculating sum:


S_(33)=(33(a_1+a_(33)))/(2)\\ \\ S_(33)=(33(3+99))/(2)=(33*102)/(2)=1683

User Pankaj K
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