Question

Find the missing endpoint given one endpoint and midpoint
endpoint-(6,-10) midpoint (-1,2)

Answer 1

`endpoint: \ ( x_(2),y_(2))= (6,-10) , \\ midpoint : \(x,y)=(-1,2) \\\\Mindpoint \ Formula : \\ (x,y)=\left ( (x_(1)+x_(2) )/(2), \frac{y_ {1}+y_(2) }{2} \right )\\\\(-1,2)=\left ( (x_(1)+ 6 )/(2), \frac{y_ {1}-10 }{2} \right )`


`\begin{cases} (x_(1)+ 6 )/(2)= -1 \ \ /\cdot 2 \\ \frac{y_ {1}-10 }{2} =2 \ \ / \cdot 2 \end{cases}\\\\\begin{cases} x_(1)+ 6 =-2 \\ y_ {1}-10 =4 \end{cases}\\ \\\begin{cases} x_(1) =-2-6 \\ y_ {1} =4+10 \end{cases}\\ \\\begin{cases} x_(1) =-8\\ y_ {1} =14 \end{cases} \\ \\Answer : \ second \ endpoint : \ (x_(1),y_(1))=(-8,14)`