256,766 views
5 votes
5 votes
סוסדיטרידGiven: AC I BD and BD bisects AC.Prove: AABD ACBD.StepStatementReasonAC I BDBD bisects ACGiven1tryType of StatementBАD

סוסדיטרידGiven: AC I BD and BD bisects AC.Prove: AABD ACBD.StepStatementReasonAC I-example-1
User Ngoral
by
2.0k points

1 Answer

10 votes
10 votes

Because BD bisects AC, we assure that the angle ABD==CBD

Now, if ABD==CBD and we know ADB=90° and CDB=90°, we can assure the remain angles must be equal: ACB==CAB

Therefore, the triangles ABD and CDB are similar. they have the same angles, they share one side, and another side is equal (AD==DC)

the triangles ABD and CDB are similar because they have all their angles equal and at least two of their sides measure the same distance


\measuredangle ABD=\measuredangle DBC

User Bytesinflight
by
2.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.