Question

What is the equation of the line, in slope-intercept form, that passes through (3, -1) and (-1,5)?

What is the equation of the line, in standard form, that passes through (4, -3) and is parallel to heline whose equation is 4x + y - 2 = 0?

Given the line 2x - 3y - 5 = 0, find the slope of a line that is perpendicular to this line.

Answer 1

its b because the others are incorrect

Answer 2

`m = (y_(2) - y_(1))/(x_(2) - x_(1)) = (5 - (-1))/(-1 - 3) = (5 + 1)/(-4) = (6)/(-4) = (3)/(-2) = -1(1)/(2)`
y - y₁ = m(x - x₁)
y - (-1) = -1¹/₂(x - 3)
y + 1 = -1¹/₂(x) + 1¹/₂(3)
y + 1 = -1¹/₂x + 4¹/₂
- 1 - 1
y = -1¹/₂x + 3¹/₂

4x + y - 2 = 0
+ 2 + 2
4x + y = 2
4x - 4x + y = -4x + 2
y = -4x + 2
y - y₁ = m(x - x₁)
y - (-3) = -4(x - 4)
y + 3 = -4(x) + 4(4)
y + 3 = -4x + 16
- 3 - 3
y = -4x + 13

2x - 3y - 5 = 0
+ 5 + 5
2x - 2x - 3y = -2x + 5
-3y = -2x + 5
-3 -3
y = ²/₃x - 1²/₃
y - (-3) = -1¹/₂(x - 4)
y + 3 = -1¹/₂(x) + 1¹/₂(4)
y + 3 = -1¹/₂x + 6
- 3 - 3
y = -1¹/₂x + 3