Question

729 = blank to the third power

Answer 1

one way is to factor and group and get every 3
729=3 times 3 times 3 times 3 times 3 times 3
so we group the ones that happen 3 times
729=(3*3*3) times (3*3*3)
we know that we can take the cube root of each group and multiply the result
729=
`( \sqrt[3]{3*3*3})( \sqrt[3]{3*3*3})`=(3)(3)=9

the answer is 9